log^4*(3x-8)=2

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Solution for log^4*(3x-8)=2 equation: 


Simplifying
log4(3x + -8) = 2

Reorder the terms:
g4lo(-8 + 3x) = 2
(-8 * g4lo + 3x * g4lo) = 2
(-8g4lo + 3g4lox) = 2

Solving
-8g4lo + 3g4lox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -8g4lo + 3g4lox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -8g4lo + 3g4lox = 0

The solution to this equation could not be determined.

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